Is this right? You have a three digit remainder with a two digit divisor.Originally Posted byNatasha1

The remainder should be less than the divisor surely?

RonL

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- May 25th 2006, 07:40 AM #1

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## Is this duable?

I found in this book the other day the following puzzle (but the book did not give any answer), if someone can do this could you explain, step by step proceedings please as I just get no where.

The question is this:

We are given the following division (each x is an unknown digit, not necessarily the same)

xxxxxxx / xx = xx8xx

There is a remainder of xxx (3 dictinct digits)

Hint: Think the long division way!

- May 25th 2006, 09:31 AM #2

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- May 25th 2006, 10:23 AM #3

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