Is this right? You have a three digit remainder with a two digit divisor.Originally Posted by Natasha1
The remainder should be less than the divisor surely?
I found in this book the other day the following puzzle (but the book did not give any answer), if someone can do this could you explain, step by step proceedings please as I just get no where.
The question is this:
We are given the following division (each x is an unknown digit, not necessarily the same)
xxxxxxx / xx = xx8xx
There is a remainder of xxx (3 dictinct digits)
Hint: Think the long division way!