Suppose that for some that is divisible byOriginally Posted byOReilly

then the exists a such that:

So from the quadratic formula we have:

Which implies that is an odd integer, say. So:

but the LHS is divisible by , and as is a square it is also divisible

by (which is ), but that would imply that is divisible by ; a

contradiction, so no such exits.

RonL