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- January 4th 2008, 01:04 PMyellow4321CRT...stuck
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. - January 4th 2008, 11:49 PMOpalg
For (d), you want a number x that is congruent to 10mod84 and to 4mod11.

I'd start by subtracting 4, and looking for x–4. This has to be a multiple of 11 that is congruent to 6mod84. So start with 6 and add multiples of 84 until you hit a multiple of 11. You get 6, 90, 194, 258, ... . When you reach a multiple of 11, don't forget to add 4 to get back to x. - January 5th 2008, 02:31 AMyellow4321
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