I could use a little guidance for this questions.
My thoughts, given the conditions n must be an even number, so n=2k where k > 3Let n be an integer greater than 6. Prove that if is n-1 and n+1 are both prime, then [tex]n^2(n^2+16) is divisible by 720. also is the converse true.
also i know that [tex] n^2 - 1 = a*b[tex] where a and b are prime and b=a+2
Could i have some help please, thanks in advance.