How may I demonstrate that there exists a rational number "r" such that x<r^2<y; where x and y are two positive real numbers.
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Originally Posted by Yeison How may I demonstrate that there exists a rational number "r" such that x<r^2<y; where x and y are two positive real numbers. Between any two numbers there is a rational number. If $0<x<y$ then $\sqrt{x}<\sqrt{y}$. Can you finish?
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