when p odd , p>3. --------- I don't know how to cintinue: a^(p-1)=1(modp) a^2=1(mod3) ....
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Is there a condition on p that is is prime?
yes, p is a prime
Okay so this might help Suppose a is a primitive root of Also,
Last edited by Kanwar245; Mar 27th 2013 at 06:44 AM.
I solved this. thanks
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