# find n such that...

$n$ is divisible by 2, 3, and 5, so try $n=2^r3^s5^t$. Then $r$ must be divisible by 3 and 5, $s$ must be divisible by 2 and 5, and $t$ must be divisible by 2 and 3. Hence one possible value for $n$ is $2^{15}3^{10}5^{6}$.