n is an integer number and p1 and p2 are primes such that p1=p2(mod4n) . prove that (n/p1)=(n/p2). --------------- I start : p1=p2 (mod4n) -> p1=4nm1+k , p2=4nm2+k (n/p1)=n^((p1-1)/2)(mod p1)=n^((4nm1+k-1)/2)(mod p1) ->>>??
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