n is an integer number and p1 and p2 are primes such that p1=p2(mod4n) .
prove that (n/p1)=(n/p2).

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I start :
p1=p2 (mod4n)
-> p1=4nm1+k , p2=4nm2+k
(n/p1)=n^((p1-1)/2)(mod p1)=n^((4nm1+k-1)/2)(mod p1) ->>>??