Assume 10 is a primitive root of p, a prime number , p!=7.

I need to prove that infinite number of this series :

31 331 3331 ...

is divided by p.

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- Mar 26th 2013, 12:42 PMuserit8primitive root
Assume 10 is a primitive root of p, a prime number , p!=7.

I need to prove that infinite number of this series :

31 331 3331 ...

is divided by p. - Mar 26th 2013, 01:08 PMKanwar245Re: primitive root
p! = 7? How is that possible?

- Mar 26th 2013, 01:25 PMuserit8Re: primitive root
I wrote it in programming form.

I mean p is prime which not equal to 7. - Mar 26th 2013, 02:15 PMKanwar245Re: primitive root
do you have to prove that everything in the series is divided by "same" p?

- Mar 26th 2013, 02:43 PMuserit8Re: primitive root
the question is from old exam in Hebow and I understand it as "the same p"

- Apr 1st 2013, 07:23 PMjohngRe: primitive root
Hi,

Here's a solution.

Attachment 27764 - Apr 14th 2013, 04:40 PMjohngRe: primitive root
I was reviewing some of my posts, and realized what I said above is perfect nonsense. The method was correct, but it was all messed up. Here's a corrected version:

Attachment 27955