# A basic number theory question,I seriously need it solved asap.

Here's one "brute strength" way to do it- all perfect squares with four decimal places are between $31^2$ and $100^2$. There are 68 such numbers. square every number form 32 to 99. "a" will be the first two digits and "b" will be the last two. Then check to see if 201a+ b is also a perfect square. For example, if n= 50, then $n^2= 2500$. a= 25 and b= 0. 201a+ b= 5025. $\sqrt{5025}= 70.88$ which is not an integer so 201a+ b is not a perfect square.