$\displaystyle \\ 10 \cdot 9 \cdot 8 \cdot 7 = 7! \\ \\ 6 \cdot 5 \cdot 4 = 5! \\ \\ \text{Does anybody know or can generate other cases like this? Where you have a product of consecutive integers, not including 2,} $ $\displaystyle \\ \text{and this product is equal to the factorial of one of the integers used in the product.} $