Dear friends,
May i check if the answer should be false?
True or false? If a and b are elements of an abelian group, then order of (ab)= lcm (order of (a), order of (b))
Thanks,
weijing
Dear friends,
May i check if the answer should be false?
True or false? If a and b are elements of an abelian group, then order of (ab)= lcm (order of (a), order of (b))
Thanks,
weijing
ord(ab) and lcm(ord(a), ord(b)) have a divisibility relationship:
so that ord(ab) always divides lcm(ord(a), ord(b).
But are they always equal? (Hint: think about inverses.)