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Math Help - Help..finding remainder of no

  1. #1
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    Help..finding remainder of no

    First 44 nos are written in order to form largest no N=12345678910111213.........424344.
    What will be remainder when N is divided by 45 ??

    i tried to solve it but didnt got anything constructive
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  2. #2
    Senior Member MaxJasper's Avatar
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    Lightbulb Re: Help..finding remainder of no

    N mod 45 = 9

    N = 2^3*3^2*171467762640433515854391275266696142117017  53789295876837964380051922139464227

    the larger number might be a prime
    Last edited by MaxJasper; October 13th 2012 at 11:02 AM.
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