# Help..finding remainder of no

• October 13th 2012, 08:03 AM
guest13
Help..finding remainder of no
First 44 nos are written in order to form largest no N=12345678910111213.........424344.
What will be remainder when N is divided by 45 ??

i tried to solve it but didnt got anything constructive
• October 13th 2012, 10:56 AM
MaxJasper
Re: Help..finding remainder of no
N mod 45 = 9

N = $2^3*3^2*171467762640433515854391275266696142117017 53789295876837964380051922139464227$

the larger number might be a prime(Shake)