First 44 nos are written in order to form largest no N=12345678910111213.........424344.

What will be remainder when N is divided by 45 ??

i tried to solve it but didnt got anything constructive

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- Oct 13th 2012, 08:03 AMguest13Help..finding remainder of no
First 44 nos are written in order to form largest no N=12345678910111213.........424344.

What will be remainder when N is divided by 45 ??

i tried to solve it but didnt got anything constructive - Oct 13th 2012, 10:56 AMMaxJasperRe: Help..finding remainder of no
N mod 45 = 9

N = $\displaystyle 2^3*3^2*171467762640433515854391275266696142117017 53789295876837964380051922139464227$

the larger number might be a prime(Shake)