a,b and c are 3 different digits of the number ABC where a,c is not equal to zero. the number got by reversing the digits is added to ABC and the sum is a perfect square. find all such 3 digit numbers.
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Hi, 100*a+10*b+c+ 100*c+10*b+100*a = 101*(a+c)+20*b Prove a+c =3,4,5... and b= 1,2,3,4... and see...