Hi,

100*a+10*b+c+

100*c+10*b+100*a =

101*(a+c)+20*b

Prove

a+c =3,4,5...

and b= 1,2,3,4...

and see...

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- October 8th 2012, 01:41 AM #1

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- October 8th 2012, 04:58 AM #2

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