The Euler's totient φ is known to be multiplicative. Letfbe de_ned byf(n) = φ (φ (n)). Is the

functionfmultiplicative? Prove your answer.

Printable View

- August 20th 2012, 08:38 PMmusngiburgerProving on Euler's totient?
The Euler's totient φ is known to be multiplicative. Let

*f*be de_ned by*f*(n) = φ (φ (n)). Is the

function*f*multiplicative? Prove your answer. - August 20th 2012, 09:44 PMDevenoRe: Proving on Euler's totient?
f will be multiplicative if gcd(a,b) = 1 implies gcd(φ(a),φ(b)) = 1. can you think of a counter-example? look at f(15).

- September 4th 2012, 12:02 AMwauwauRe: Proving on Euler's totient?
@musngiburger

since is always even for n>2 never true !!!!!!