How would I prove that f(x) = [x] is surjective, where [x] denotes the bracket function
I know how to prove that something is surjective, but I'm stuck on this particular example
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How would I prove that f(x) = [x] is surjective, where [x] denotes the bracket function
I know how to prove that something is surjective, but I'm stuck on this particular example
What is the bracket function?
Also known as the floor function, gauss brackets?Quote:
Originally Posted by emakarov
In proofs of surjection, knowing the domain and codomain is essential. For example, f(x) = [x] is not surjective if f is considered fromto
to
. So I'll assume that
.
We need to prove that for everythere is an
such that [x] = n. Can you find several such x for n = 3?