
factors of number
X=A_{1}*A_{2}*A_{3}*.......*A_{30}*A_{31}*A_{32}
A_{i} = 32+i*B_{i}
127=>Bi>=20
32=>i>=1
i already know the 3rd to 15th digits of X,is there any easy method that i can get Ai and Bi that meets the above conditions.
FOR EXAMPLE
X = 39643349072461066000314567734381141719323562950043 570493911241444710177308672000000 = 129*232*359*452*582*158*179*200*221*242*263*284*30 5*326*347*368*389*410*431*452*473*494*515*536*557* 578*599*620*641*662*683*704
129 = 97*1 + 32
232 = 100*2 + 32
359 = 109*3 + 32
.....
.....
704 = 21*32 + 32
if 3rd to 15th digits of X is already known(in this case 6433490724610),can i get a set of Bi that meets the above conditions