simplify the following logarithms to a single log term

log(8x²)+log(27)^1/3 = log(4/x²)

i can use the law of logs to some degree in this question but just cant get it down into a single logarithm.. please help?

Note 27^1/3=3
So we have log(8x^2)+log3=log(4/x^2)

log(24x^2)= log (4/x^2) So 24x^2= 4/x^2 x^4 = 1/6

i can follow that up to the last part :24x^2= 4/x^2 x^4 = 1/6 can u just explain how, mainly the x^4 thats confusing me where did that come from?

I should have used a space.

24x^2=4/x^2 Multiply both sides by x^2 Then get 24x^4=4 Divide both sides by 24 Then get x^4=4/24 So x^4=1/6

i understand now thats great thank you :)