log(8x²)+log(27)^1/3 = log(4/x²)

i can use the law of logs to some degree in this question but just cant get it down into a single logarithm.. please help?

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- Apr 13th 2012, 02:50 AMbobmarly12345simplify the following logarithms to a single log term
log(8x²)+log(27)^1/3 = log(4/x²)

i can use the law of logs to some degree in this question but just cant get it down into a single logarithm.. please help? - Apr 13th 2012, 02:56 AMprincepsRe: simplify the following logarithms to a single log term
$\displaystyle \log a+\log b=\log (a\cdot b)$

$\displaystyle \log a-\log b=\log\left(\frac{a}{b}\right)$ - Apr 13th 2012, 03:11 AMbiffboyRe: simplify the following logarithms to a single log term
Note 27^1/3=3

So we have log(8x^2)+log3=log(4/x^2)

log(24x^2)= log (4/x^2) So 24x^2= 4/x^2 x^4 = 1/6 - Apr 13th 2012, 03:26 AMbobmarly12345Re: simplify the following logarithms to a single log term
i can follow that up to the last part :24x^2= 4/x^2 x^4 = 1/6 can u just explain how, mainly the x^4 thats confusing me where did that come from?

- Apr 13th 2012, 04:18 AMbiffboyRe: simplify the following logarithms to a single log term
I should have used a space.

24x^2=4/x^2 Multiply both sides by x^2 Then get 24x^4=4 Divide both sides by 24 Then get x^4=4/24 So x^4=1/6 - Apr 13th 2012, 04:33 AMbobmarly12345Re: simplify the following logarithms to a single log term
i understand now thats great thank you :)