Thread: Solve for a and b if:

Solve for a and b if: (jb)/(1-j)=(a-j)2j

Any help will be much appreciated.
Thanks in advance

Originally Posted by Scoplex

Solve for a and b if: (jb)/(1-j)=(a-j)2j

Any help will be much appreciated.
Thanks in advance

Originally Posted by princeps

How did you arrive at 2 + 2aj?
Isn't it 2aj - 2j^2 ?

Originally Posted by Wilmer

How did you arrive at 2 + 2aj?
Isn't it 2aj - 2j^2 ?

Well, you sure got me confused! We start with:
(j*b) / (1 - j) = 2*j*(a - j)

We're to solve for a and b;
b is straightforward: b = [2j(a - j)(1 - j)] / j

Solving for a leads to:
a = [2j(j - 1) - b] / [2(j -1)]

That checks out perfectly with the initial equation.
And there's loads of solutions; examples with all positive integers:
(a,b,j) = (1,2,2), (2,4,3), (1,8,3), (3,6,4), (4,8,5)

Can you explain why you jump to j^2 = -1 ?

I think that is imaginary unit .

Originally Posted by princeps

I think that is imaginary unit .

Why? Absolutely no mention of that in original post.
Anyway, ask me if I care