I can't seem to figure out the logic behind this problem.

Would this problem have something to do with mode?

I know I am missing the main point of this problem.(Headbang)

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- Jan 16th 2012, 06:34 PMVeronica1999squares
I can't seem to figure out the logic behind this problem.

Would this problem have something to do with mode?

I know I am missing the main point of this problem.(Headbang) - Jan 17th 2012, 12:58 AMprincepsRe: squares
Since is an odd number it must be perfect square also . So:

Now, if we make substitution we can write :

This equality has integer solutions only if is power of so must be an odd number so we shall make substitution and therefore :

It is obvious that both and must be powers of and this is possible only if , therefore :