Given that Find the set of values of for which How do I solve for n?
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Originally Posted by Punch Given that Find the set of values of for which How do I solve for n? Get your calculator out and try a few values You may need to prove that there is but a single positive root to . CB
Originally Posted by CaptainBlack Get your calculator out and try a few values You may need to prove that there is but a single root to . CB Does that mean that I have to use a guess and check method?
Originally Posted by Punch Does that mean that I have to use a guess and check method? That would do it, yes. But don't forget you need to show this has a single positive root.
Originally Posted by CaptainBlack That would do it, yes. But don't forget you need to show this has a single positive root. Does that mean I have to show b^2-4ac=0? But how do i go about doing that for an equation with a power
Originally Posted by Punch Does that mean I have to show b^2-4ac=0? But how do i go about doing that for an equation with a power No, what you need to do is show that: is monotonic and changes sign between and say , then since is continuous it has a single root and it lies between and . CB
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