Let *(x) be the function that calculates the sum of positive integer divisors of x.

i.e *(6) = 1+2+3+6 = 12

How do I go about finding all x such that *(x) = 12?

Thanks

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- Oct 21st 2011, 11:16 PMjzelltSum of positive integer divisor
Let *(x) be the function that calculates the sum of positive integer divisors of x.

i.e *(6) = 1+2+3+6 = 12

How do I go about finding all x such that *(x) = 12?

Thanks - Oct 22nd 2011, 07:24 AMroninproRe: Sum of positive integer divisor
You definitely know that $\displaystyle x< 12$, so how about using brute force?

- Oct 22nd 2011, 02:05 PMjzelltRe: Sum of positive integer divisor
I need to find a pattern or formula of some sort. The next problem is to find x such that *(x) = 56. Brute force isn't exactly ideal here...