A number r is algebraic if there is a nonzero polynomial p(x) with integer coefficients such that r is a root of p(x) = 0. Prove that every rational number is an algebraic number.
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Originally Posted by thamathkid1729 A number r is algebraic if there is a nonzero polynomial p(x) with integer coefficients such that r is a root of p(x) = 0. Prove that every rational number is an algebraic number. Let q be any rational number. q=a/b, where a and b are integers. bq-a=0 bx-a is the nonzero polynomial p(x) with integer coefficients such that q is a root of p(x)=0. So, every rational number is an algebraic number.
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