How do I show that this (see below) has no solutions?

$\displaystyle 2+b^3\equiv b \ (\text{mod} \ 5)$

Results 1 to 3 of 3

- Oct 5th 2011, 11:08 AM #1

- Joined
- Mar 2010
- From
- Florida
- Posts
- 3,093
- Thanks
- 10

- Oct 5th 2011, 11:19 AM #2

- Oct 5th 2011, 11:34 AM #3

- Joined
- Mar 2010
- From
- Florida
- Posts
- 3,093
- Thanks
- 10