Find all pairs of positive integers x and y that safisfy the equation: 1/x - 1/y = 1/2005
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x, y 1604, 8020 1980, 158796 2000, 802000 2004, 4018020
Thanks Paul for finding the solutions!
Last edited by phgao; May 5th 2005 at 02:29 AM.
Hi there, i was wondering how you rearrange my first equation: Namely: 1/x - 1/y = 1/2005 Into: y = -2005 + (2005^2/2005-x) Thanks!
Ok solved. No need to post an answer. To solve add and subtract 2005^2 from the numerator... then it falls in place. Thanks anyway.
how can you prove it tho? how do you work it out? x, y 1604, 8020 1980, 158796 2000, 802000 2004, 4018020 ??
Into: y = -2005 + (2005^2/2005-x) Why is it like that? Why isn't it y= -2005 + (2005^2/x-2005)
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