Find all pairs of positive integers x and y that safisfy the equation:

1/x - 1/y = 1/2005

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- May 4th 2005, 01:54 AMphgao1/x - 1/y = 1/2005
Find all pairs of positive integers x and y that safisfy the equation:

1/x - 1/y = 1/2005 - May 4th 2005, 11:49 PMpaultwang
x, y

1604, 8020

1980, 158796

2000, 802000

2004, 4018020 - May 5th 2005, 01:51 AMphgao
Thanks Paul for finding the solutions!

- Jul 13th 2005, 01:23 AMphgao
Hi there, i was wondering how you rearrange my first equation:

Namely: 1/x - 1/y = 1/2005

Into: y = -2005 + (2005^2/2005-x)

Thanks! - Jul 13th 2005, 04:37 AMphgao
Ok solved. No need to post an answer.

To solve add and subtract 2005^2 from the numerator... then it falls in place. Thanks anyway. - Sep 5th 2005, 08:06 AMSbD
how can you prove it tho? how do you work it out?

x, y

1604, 8020

1980, 158796

2000, 802000

2004, 4018020

?? - Sep 10th 2005, 06:50 AMardnas
*Into: y = -2005 + (2005^2/2005-x)*

Why is it like that?

Why isn't it y= -2005 + (2005^2/__x-2005__)