If I understand what you are saying, the question is asking if we can multiply any two of the members of this series and come up with another member of the series.Originally Posted byNatasha

Similar to the last question, we may represent the series as .

So take two members of this series, and . Their product is . This is supposed to be another member of the series, so let . Solving for q:

. But q must be an integer, and it isn't for any n,m. Thus NO product of members is a member of the series.

-Dan