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Math Help - Factorial Problem

  1. #1
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    Lightbulb Factorial Problem

    Hi All,
    I want to know the value of below:

    Sum of [(n-2)! / (n-k)!], where n=59 and k begins with 2 and ends with 59.
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  2. #2
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    Re: Factorial Problem

    You mean \displaystyle \sum_{k=2}^{59}\frac{(59-2)!}{(59-k)} ?
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  3. #3
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    Re: Factorial Problem

    Quote Originally Posted by pickslides View Post
    You mean \displaystyle \sum_{k=2}^{59}\frac{(59-2)!}{(59-k)} ?



    yes absolutely !!
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  4. #4
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    Re: Factorial Problem

    (59-k) !
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  5. #5
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    Re: Factorial Problem

    Quote Originally Posted by pickslides View Post
    You mean \displaystyle \sum_{k=2}^{59}\frac{(59-2)!}{(59-k)!} ?

    I want to know the value for above
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  6. #6
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    Re: Factorial Problem

    Quote Originally Posted by pickslides View Post
    You mean \displaystyle \sum_{k=2}^{59}\frac{(59-2)!}{(59-k)} ?
    Should the be ! in the denominator?
    \sum_{k=2}^{59}\frac{(59-2)!}{(59-k)\color{red}!}
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  7. #7
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    Re: Factorial Problem

    yes .
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  8. #8
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    Re: Factorial Problem

    Here is the value.

    \sum_{k=2}^{59}\frac{(59-2)!}{(59-k)!}=110163588853530184980727482893521304479399855  114493057608241578732074256106650
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  9. #9
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    Re: Factorial Problem

    Quote Originally Posted by Plato View Post
    Here is the value.

    \sum_{k=2}^{59}\frac{(59-2)!}{(59-k)!}=110163588853530184980727482893521304479399855  114493057608241578732074256106650

    Thank U man
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  10. #10
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    Re: Factorial Problem

    Hi How did u calculated this ??? can u tell me the procedure ??
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