1. ## Factorial Problem

Hi All,
I want to know the value of below:

Sum of [(n-2)! / (n-k)!], where n=59 and k begins with 2 and ends with 59.

2. ## Re: Factorial Problem

You mean $\displaystyle \displaystyle \sum_{k=2}^{59}\frac{(59-2)!}{(59-k)}$ ?

3. ## Re: Factorial Problem

Originally Posted by pickslides
You mean $\displaystyle \displaystyle \sum_{k=2}^{59}\frac{(59-2)!}{(59-k)}$ ?

yes absolutely !!

(59-k) !

5. ## Re: Factorial Problem

Originally Posted by pickslides
You mean $\displaystyle \displaystyle \sum_{k=2}^{59}\frac{(59-2)!}{(59-k)!}$ ?

I want to know the value for above

6. ## Re: Factorial Problem

Originally Posted by pickslides
You mean $\displaystyle \displaystyle \sum_{k=2}^{59}\frac{(59-2)!}{(59-k)}$ ?
Should the be $\displaystyle !$ in the denominator?
$\displaystyle \sum_{k=2}^{59}\frac{(59-2)!}{(59-k)\color{red}!}$

yes .

8. ## Re: Factorial Problem

Here is the value.

$\displaystyle \sum_{k=2}^{59}\frac{(59-2)!}{(59-k)!}=110163588853530184980727482893521304479399855 114493057608241578732074256106650$

9. ## Re: Factorial Problem

Originally Posted by Plato
Here is the value.

$\displaystyle \sum_{k=2}^{59}\frac{(59-2)!}{(59-k)!}=110163588853530184980727482893521304479399855 114493057608241578732074256106650$

Thank U man

10. ## Re: Factorial Problem

Hi How did u calculated this ??? can u tell me the procedure ??