Thread: Exponential cipher

I tried to work through this ex in my book which is not typical of the ex I have done and I am confused after first part
for part a I worked out that inverse of 5 in Z36 is 29. hope this is correct
but I have no clue as to where to and how to start part b - which is attached here. Can someone please guide me in detail as I am studying this for the first type.

Originally Posted by vidhi96

I tried to work through this ex in my book which is not typical of the ex I have done and I am confused after first part
for part a I worked out that inverse of 5 in Z36 is 29. hope this is correct

This is correct :

Originally Posted by vidhi96

but I have no clue as to where to and how to start part b - which is attached here. Can someone please guide me in detail as I am studying this for the first type.

The table gives you a correspondence . So for a letter , the cipher letter is (I didn't check, but in order to apply , one must have ).

When you have a word, it's a sequence of letter : you encrypt every letter of this sequence and have this way a sequence of cipher letter. It's your cipher text.

i am more confused. What I figured out by now is message ext is <23 8 5 14> spelling WHEN.

so now I need to find c - which is chipher text is that correct

Originally Posted by pece

This is correct :



The table gives you a correspondence . So for a letter , the cipher letter is (I didn't check, but in order to apply , one must have ).

When you have a word, it's a sequence of letter : you encrypt every letter of this sequence and have this way a sequence of cipher letter. It's your cipher text.

Originally Posted by vidhi96

i am more confused. What I figured out by now is message ext is <23 8 5 14> spelling WHEN.

Now you have to apply to each of these numbers and then retranslate the result into letters.

Originally Posted by pece

Now you have to apply to each of these numbers and then retranslate the result into letters.

Ok I'll try and type it and send it to you tomorrow