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- July 1st 2011, 09:26 PM #1

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## (x+1)! + (y+1)! = x^2 x y^2

Hello, any assistance on the problem would be much appreciated. I have a vague idea but cant quite remember what to do.

(+1)! + (**x**+1)! =**y**^2 x**x**^2, how many pairs such that**y**and*x*are a pair of positive, non-negative integers?*y*

Any help would be great, my maths tutor set this and i honestly cant quite remember what to do in this case.

Cheers

- July 1st 2011, 11:30 PM #2

- July 1st 2011, 11:36 PM #3

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- July 2nd 2011, 12:21 AM #4

- July 2nd 2011, 08:12 PM #5

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- July 2nd 2011, 09:33 PM #6