Fibonacci sequence divisibility proof
Hello All,
I am thoroughly lost with how to construct this proof:
Let F(sub)n be the nth Fibonacci number.
Prove that, if 3|n then 2|F(sub)n.
Would induction be a recommendation, and if so, could anyone please recommend a base assumption to begin with?
Thank you very much for your time,
Panglot
Re: Fibonacci sequence divisibility proof
Quote:
Originally Posted by
panglot
Hello All,
I am thoroughly lost with how to construct this proof:
Let F(sub)n be the nth Fibonacci number.
Prove that, if 3|n then 2|F(sub)n.
Would induction be a recommendation, and if so, could anyone please recommend a base assumption to begin with?
Thank you very much for your time,
Panglot
If and only if can be placed.
Are you familiar with the theorem that says:
if and only if
.
Re: Fibonacci sequence divisibility proof
What you want to prove is that

is divisible by 2 for any positive integer n. It is easy to do that by induction on n.
If n= 1,
}= F_3= 2)
which is divisible by 2.
Assume that, for some k,

is divisible by 2. That is, that

for some integer m.
Then
.
Re: Fibonacci sequence divisibility proof
Quote:
Originally Posted by
HallsofIvy
What you want to prove is that

is divisible by 2 for any positive integer n. It is easy to do that by induction on n.
If n= 1,
}= F_3= 2)
which is divisible by 2.
Assume that, for some k,

is divisible by 2. That is, that

for some integer m.
Then
}= F_{3k+ 3}= F_{3k+1}+ F_{3k+2}= F_{3k+1}+ (F_{3k}+ F_{3k+1})= 2m+ 2F_{3k+1})
.
I'm sorry, but I don't quite follow how you arrived at the last two in the series of equivalences:
= F_{3k+1}+ (F_{3k}+ F_{3k+1})= 2m+ 2F_{3k+1}
Re: Fibonacci sequence divisibility proof
Quote:
Originally Posted by
panglot
I'm sorry, but I don't quite follow how you arrived at the last two in the series of equivalences:
= F_{3k+1}+ (F_{3k}+ F_{3k+1})= 2m+ 2F_{3k+1}
By definition of Fibonacci sequence.
F_{k+2}=F_{k+1}+F_{k}.