calculate in i know how to go about this question, im just a little confused... does , because we are working in ?

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Originally Posted by wik_chick88 calculate in i know how to go about this question, im just a little confused... does , because we are working in ? No, if that were the case it would be the additive identity. Just reduce the coefficient mod 5

Originally Posted by wik_chick88 calculate in i know how to go about this question, im just a little confused... does , because we are working in ? Roots of: g(x)=2x^2 - x - 1=0 are: 1 and -1/2 Say f(x)=x^3 + 2x^2 + 3x - 1, f(1)!=f(-1/2)!=0 gcd((f(X),g(x))=1

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