Can't figure out why -(7/3)=-(4/3) Anyone can make it simple for me.
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Originally Posted by joi Can't figure out why -(7/3)=-(4/3) Anyone can make it simple for me. $\displaystyle \binom{7}{3}=\binom{1}{3}=1\,,\,\,\binom{4}{3}= \binom{1}{3}=1$ , when taking $\displaystyle 4,7=\!\!\pmod 3$ Tonio
Thanks Tonio. Can somebody evaluate (7/79). I keep getting (-1). The answer in the back of the book is 1. Obviously I am making a mistake.
I get (7/79) = -(2/7) = -(1/7) = -1 Maybe the answer in the back of the book is wrong?
Originally Posted by AmateurStudent I get (7/79) = -(2/7) = -(1/7) = -1 Maybe the answer in the back of the book is wrong? I agree
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