Sequence embedding?

Introduction:
I'm an Electronics Engineer with a love for math so due to my background pardon me if my description is inadequate (I tried hard to make it formally correct).

Context and motivation:
I have been working with Sidel'nikov sequences and through exploratory analysis I found that some sequences are contained in lengthier ones.

Conditions:
Consider only binary sequences and $\displaystyle \mathbb{F}_{p}$ for $\displaystyle$p$$a Fermat prime. Although not the original definition, the positions of "1" in a Sidel'nikov sequence can be determined using the Zech log, \displaystyle Z_{\alpha }^{\left ( p \right )}\left ( n \right ):\textup{ord}_{p}\left ( \alpha \right )=1+\alpha ^{n}$$ or alternatively $\displaystyle$\alpha ^{Z\left ( n \right )}\equiv _{p}1+\alpha ^{n}$$with \displaystyle \alpha a primitive element of \displaystyle \mathbb{F}_{p} and \displaystyle n=1,3,5,\cdots ,p-1$$. To be entirely correct $\displaystyle$n$$belongs to a prime residue group, so \displaystyle \left ( n,p-1 \right )=1 but since we are restricting ourselves to Fermat primes then we can just consider \displaystyle n$$ to be in the set of all the odd integers less than $\displaystyle$p$$. A numerical example using Mathematica: For a sequence of length 16 with primitive element 3, Sort[Table[Zech[n,3,17],{n,1,17-1,2]] {4, 6, 7, 10, 11, 12, 13, 15} For a sequence of length 256 with primitive element 3, and taking values (mod 16) Mod[Sort[Table[Zech[n,3,257],{n,1,257-1,2]],16] {4,6,7,9,13,...,5,10,11,12,13,15} where we can see that the lengthier sequence is wrapped by the smaller seq. I'm interested in the values of \displaystyle n$$ that satisfy both congruences. So the question is: what values of $\displaystyle$n satisfy simultaneously
$\displaystyle \alpha^{Z_\alpha ^{(257)} (\textup{mod} \: 16)}$ and $\displaystyle \alpha^{Z_\alpha ^{(17)}$?

I've tried to attack the problem using instead
$\displaystyle 3^{n} \in \left \{ 3^{2i}-1:i=0,1,\cdots \frac{17-1}{2}-1 \right \}\Rightarrow 3^{n\left ( \textup{mod}\: 16 \right )} \in \left \{ 3^{2j}-1:j=0,1,\cdots \frac{257-1}{2}-1 \right \}$
but one of the problems is that of ordering. Any advise please?