Originally Posted by

**steph3824** Ok, I understand that method. But I thought that that is what you want to do when you want to write π as a product of disjoint cycles. Writing π as a product of disjoint cycles would be (1 4 5 2 7 8 9 3).

SO, back to my original question, if I want to write π like π=1 2 ....9 with the images underneath, I'm guessing the images come from my product of disjoint cycles above? In other words, would π written in standard form be...

π=1 2 3 4 5 7 8 9

...4 7 1 5 2 8 9 3

??

Yes, but don't forget 6 which is mapped to itself.

Also, I know that the order for a disjoint permutation is ord(π1, π2...)=lcm(ord(π1), ord(π2),...), but I don't know how to find the order for a non-disjoint permutation. I would appreciate an explanation of how to find it.