Thread: Square and Cube Induction Proof

Hey all, some help with the following proof would be appreciated:

For all integers k >= 2, k^2 < k^3

I believe induction can be used here. Thanks a bunch!

divide by k^2 on both sides.

1<k.

Since k>=2, this will always hold true.

The actual proof, of course, would go the other way:
Since , . Now multiply on both sides by the positive number .