A polynomial with integer coeffiecients is an expression of the form where . If , is said to be of degree . Denoting the set of all such polynomials as , show that is a ring with respect to a natural definition of addition and multiplication of polynomials.
So, Let , where and
. Now we have
Clearly, anwhere , the coefficient will be , which is an integer. All of the rest of the terms will remain unchanged and so will necessarily have integer coefficients, therefore and we conclude that the sum of two functions in is also in .
OK. I'm trying here but I'm stuck. Help?
A polynomial of degree k that normally has k + 1 terms can be considered as having n + 1 terms for any n >= k; just make the coefficients to be zero. The definition does not say that coefficients have to be non-zero. We are not talking about a degree here. Thus, when we need to add two polynomials, we can assume that they have the same number of terms.
Do you doubt that the sum of two polynomials with integer coefficients is another such polynomial? For example, what about ?
No, I don't doubt that the sum of polynomials with integer coefficients will result an anything but another polynomial with said coeffiecients. I'm new to the subject and therefore I am having trouble with answering the questions. How would you show that is a ring wrt multiplication and addition? I would appreciate your help. Thank you.
Originally Posted by emakarov
One has to check, first, that is closed under the operations, i.e., addition and multiplication do not return results that are outside of , and, second, all the ring axioms.
The definition of addition and multiplication is given here, from where it is pretty clear that is closed under these operations. Axioms about addition are pretty simple. Associativity of multiplication and distributivity can be proved directly from the definitions above by working with big sums, but there may be a more elegant way. I'll think about this more.