6x + 2y + 2z = -2

2x + 2/3y + 1/3z = 1

x + 2y - z = 0

This is part of a numerical methods tutorial sheet, I cant seem to solve them when im asked to use a certain digit arithmetic with rounding, would really appreciate if someone could go through it painfully slowly. I have answer in front of me but cant get it, I think im missing something that should be rather simple.

Thanks

Nappy