the following does not hold?
$\displaystyle a^{10} + b^{10} + c^{10} = 11d^2 \text{ mod } p$
I tried p = 3 and p = 11, and I couldn't get anywhere, since I can still have trivial solutions.
Thanks!
-- Josh
the following does not hold?
$\displaystyle a^{10} + b^{10} + c^{10} = 11d^2 \text{ mod } p$
I tried p = 3 and p = 11, and I couldn't get anywhere, since I can still have trivial solutions.
Thanks!
-- Josh
What's your question? Are you looking for a prime for which the above equation doesn't have a non-trivial solution? Then $\displaystyle p=11$ works since assuming $\displaystyle (a,b,c)\ne (11,11,11)$ then the RHS is zero but $\displaystyle 1\leqslant \text{LHS}\leqslant 3$.