How to go about this problem?
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Now as Soroban said Sorry about the mistake
Last edited by dwsmith; December 11th 2010 at 10:16 AM. Reason: corrected due to error
thanks a lot
Originally Posted by dwsmith I'm not sure I get the above: the powers of 7 have a periodicy length of 4, and all the powers of 7 which are 2 mod 4 end with 49, so the difference must be 9-4 = 5 ...Is this what you meant? Also, why to write and not simply ? Tonio
Hello, pranay! We have: . Then: . Hence: . The difference is: .
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