Originally Posted by

**mybrohshi5** Not sure if this post should go here so if it would be better else where would a Mod please move this :D Thanks!

Here is the question i am working on and it seems simple enough but i just wanted a second opinion

**For what value(s) of b is $\displaystyle b^a $ **__>__ ab for all real numbers a?

if b is __>__ 2 then $\displaystyle b^a $ will be __>__ ab

but

I also notice that if a = 1 then b can also = 1 so i am not sure what to do with that.

Any help on how to prove this problem would be great :D

Thank you