How many numbers between 1 and 100 (excluded) satisfy that the sum of the squares of its digits divides the number? Help please Thank you.
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Originally Posted by guidol92 How many numbers between 1 and 100 (excluded) satisfy that the sum of the squares of its digits divides the number? Help please Thank you. Well clearly no one digit number greater than one satisfies this, so let's only look at two digit numbers. Let where We need to solve the Diophantine Equation . Before I dive right in, let's see if you can do this.
Originally Posted by chiph588@ Well clearly no one digit number greater than one satisfies this, so let's only look at two digit numbers. Let where We need to solve the Diophantine Equation . Before I dive right in, let's see if you can do this. Do you notice the word "divides", not "equal to" in x^2+y^2 = 10x+y.
Originally Posted by Shanks Do you notice the word "divides", not "equal to" in x^2+y^2 = 10x+y. Pardon?
A computer search finds the numbers: 1, 10, 20 and 50.
@Chip so
Originally Posted by elemental @Chip so Ohh, I read the question wrong as Shanks was pointing out.
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