Prove, that if (m,n) = 1 // m and n are two different primes
then (2^m -1, 2^mn -1/2^m -1) = 1
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So basically we have to show that doesn't divide (since is prime)
Now this cannot always happen since we may choose, say (3, 7).
Last edited by PaulRS; November 19th 2010 at 04:00 PM.
Reason: errors, sorry for making so many this time
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