If you're given , and , then is the additive inverse of . Similarly, if , then is the multiplicative inverse of .

Calculating the additive inverses is relatively easy; all you need to do is find an such that with being an element of the residue system (Its very similar for the other one).

In calculating the multiplicative inverse of there is usually no quick of way of doing it (if you have a knowledge of Euler's theorem, then it could be used to get to the answer as well). However, since you're looking at mod 13, you can find the inverse by the method of exhaustion; i.e. find out what 7*1, 7*2, 7*3, ... ,7*13 are and see which results in the value of 1. So in your case, so 2 is the multiplicative inverse of 7. The other one is done in a similar fashion.

Does this make sense? Can you proceed?