Dear All,
A question that I have been trying to prove ;
prove that all postive numbers (m), the units digit of m^5 - m is 0 ?
Since the integer is in base 10,
suppose m=0 then (0)^5 - 0 = 0 ( this is not a postive int)
m=1 then (1)^5 - 1 = 0
m=2 then (2)^5 - 2 = 30 ....
.......
using (10m + u)^2 is a method of proving however I have yet to prove it for this question.
regards
S.J