If pq|(n^2) proof that pq|n...
p is prime and q is prime and pis not equal to q.
My proof I used the contrapositive to proof it..
if pq not divisble by n then pq is not divisible by n squared
*!= is not equal to..
Short version of proof
n!=pqk where k is element of Z
(n)^2 !=pqc where c=kpq is element of Z
please check if this is right...
How will you prove this directly?