Hi, I've started solving this problem, but I don't know how to finish it off. Find all ordered pairs of integers (x,y) such that: so far i have completed the square to get the following: Thanks!
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You have a difference of squares. What differences of squares can give you 17?
would (y+x+1)(y-x-1) = 17 work?
Originally Posted by hsidhu would (y+x+1)(y-x-1) = 17 work? Yes, you have transformed the problem into one of integer factorization, which is rather easy here since 17 is prime. Four candidate solutions: y+x+1 = 1 AND y-x-1 = 17 y+x+1 = 17 AND y-x-1 = 1 y+x+1 = -1 AND y-x-1 = -17 y+x+1 = -17 AND y-x-1 = -1
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