# Stumped on a Proof

The decimal expansion of $abcabc$, is $a\cdot10^5+b\cdot10^4+c\cdot10^3+a\cdot10^2+b\cdot 10+c=10^3(a\cdot10^2+b\cdot10+c)+a\cdot10^2+b\cdot 10+c$.