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Thread: question and trial

  1. August 9th 2010, 11:22 PM #1
    fxs12
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    question and trial

    <br /> \begin{array}{l}<br /> prove{\rm that} \\ <br /> {\rm gcd(a,b)} \le {\rm a - b , a} \succ {\rm b} \\ <br /> {\rm solution:} \\ <br /> {\rm note}\;{\rm that}\;{\rm gcd(a,b) = gcd(a, - b)} \\ <br /> \Rightarrow {\rm d\backslash a , d\backslash - b} \Rightarrow {\rm d\backslash a + - b} \\ <br /> {\rm this}\,\;{\rm means}\;{\rm that}\;{\rm d} \le {\rm a - b } \Rightarrow {\rm gcd(a,b)} \le {\rm a - b }{\rm .} \\ <br /> \\ <br /> \end{array}
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  2. August 10th 2010, 12:42 AM #2
    Swlabr
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    Is there a question here, or are you just wanting someone to look over your answer? It looks good to me...
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